The lock pin is sticking in the shifter.
The lock pin is working perfectly. The solenoid at the shifter has a green and yellow wire going to it. When the key is on, the yellow sends 12 volts to the solenoid, but there is no ground. If I send the green wire to ground, it activates the solenoid. I have to assume that when the brakes are applied, it should close the ground circuit, but that's not happening.
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The lock pin is working perfectly. The solenoid at the shifter has a green and yellow wire going to it. When the key is on, the yellow sends 12 volts to the solenoid, but there is no ground. If I send the green wire to ground, it activates the solenoid. I have to assume that when the brakes are applied, it should close the ground circuit, but that's not happening.
Not sure what is going on here, I read that you said the park release solenoid works fine??
It is functional, meaning if I ground the green wire going to it, that activates the park release solenoid. But it will not activate on it's own.
I never did find out why the shifter solenoid wasn't getting a ground to shift out of park. So I wired in a permanent ground to the green wire. What this did is when the ignition switch is turned on, it activates the solenoid so I am able to shift out of park. All this does is take the brake pedal out of the scenario.
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